Learn

Friday, 9 October

NEET UG 2024 · Chemistry · Question 70

NEET 2024 Chemistry, question 70

Question 70 of the NEET 2024 paper (code T2) is a Chemistry question from Chemical Kinetics. Its idea, Arrhenius Equation at Two Temperatures, was asked twice, both in 2024, across NEET 2017–2026. The NTA final answer key gives option 2.

Updated 2026-10-08

Q70 · Chemistry

Activation energy of any chemical reaction can be calculated if one knows the value of

  1. 1orientation of reactant molecules during collision.
  2. 2rate constant at two different temperatures.Official answer
  3. 3rate constant at standard temperature.
  4. 4probability of collision.

Official answer: option 2 · NTA final answer key

Same idea

Arrhenius Equation at Two Temperatures, in other papers

NEET asked this idea twice, both in 2024. The other question below.

  • 2024 Q88The rate of a reaction quadruples when temperature changes from 27°C to 57°C. Calculate the energy of activation. Given R = 8.314 J…Numerical · Medium

Arrhenius Equation at Two Temperatures: every question and how it was framed

The chapter

Chemical Kinetics in ten years of NEET

21 questions from 2017–2026, asked in 10 of 10 papers, about 2.0 a paper. Chemical Kinetics alone had 21.

Chemical Kinetics: questions per paper

0242’172’182’192’202’212’222’233’242’252’26