NEET UG 2024 · Chemistry · Question 88
NEET 2024 Chemistry, question 88
Question 88 of the NEET 2024 paper (code T2) is a Chemistry question from Chemical Kinetics. Its idea, Arrhenius Equation at Two Temperatures, was asked twice, both in 2024, across NEET 2017–2026. The NTA final answer key gives option 3.
Updated 2026-10-08
Q88 · Chemistry
The rate of a reaction quadruples when temperature changes from 27°C to 57°C. Calculate the energy of activation.
Given R = 8.314 J K mol, log 4 = 0.6021
- 13.80 kJ/mol
- 23804 kJ/mol
- 338.04 kJ/molOfficial answer
- 4380.4 kJ/mol
Official answer: option 3 · NTA final answer key
Same idea
Arrhenius Equation at Two Temperatures, in other papers
NEET asked this idea twice, both in 2024. The other question below.
- 2024 Q70Activation energy of any chemical reaction can be calculated if one knows the value ofOne-line MCQ · Easy
Arrhenius Equation at Two Temperatures: every question and how it was framed
The chapter
Chemical Kinetics in ten years of NEET
21 questions from 2017–2026, asked in 10 of 10 papers, about 2.0 a paper. Chemical Kinetics alone had 21.