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Friday, 9 October

NEET UG 2024 · Chemistry · Question 69

NEET 2024 Chemistry, question 69

Question 69 of the NEET 2024 paper (code T2) is a Chemistry question from Aldehydes, Ketones and Carboxylic Acids. Its idea, Preparation of Aldehydes, Ketones and Acids, was asked 3 times, all in 2024, across NEET 2017–2026. The NTA final answer key gives option 4.

Updated 2026-10-08

Q69 · Chemistry

Identify the correct reagents that would bring about the following transformation.

[C6_6H11_{11}]-CH2_2-CH=CH2_2 →\to [C6_6H11_{11}]-CH2_2-CH2_2-CHO

The figure, described in words

Transformation drawn with cyclohexyl rings: cyclohexyl-CH2-CH=CH2 → cyclohexyl-CH2-CH2-CHO.

  1. 1(i) BH3_3 (ii) H2_2O2_2/O⊖\overset{\ominus}{\mathrm{O}}H (iii) alk. KMnO4_4 (iv) H3_3O⊕^{\oplus}
  2. 2(i) H2_2O/H+^+ (ii) PCC
  3. 3(i) H2_2O/H+^+ (ii) CrO3_3
  4. 4(i) BH3_3 (ii) H2_2O2_2/O⊖\overset{\ominus}{\mathrm{O}}H (iii) PCCOfficial answer

Official answer: option 4 · NTA final answer key

Same idea

Preparation of Aldehydes, Ketones and Acids, in other papers

NEET asked this idea 3 times, all in 2024. The other 2 questions below.

  • 2024 Q59Match List I with List II. List I (Reaction) | List II (Reagents/Condition) A. [cyclohexylidenecyclohexane] →\to 2 [cyclohexanone] | I.…Match the lists · Medium
  • 2024 Q97For the given reaction: [C6_6H11_{11}]-CH=CH-[C6_6H11_{11}] →KMnO4/H+\xrightarrow{\mathrm{KMnO_4/H^+}} 'P' (major product) 'P' isOne-line MCQ · Easy

Preparation of Aldehydes, Ketones and Acids: every question and how it was framed

The chapter

Aldehydes, Ketones and Carboxylic Acids in ten years of NEET

27 questions from 2017–2026, asked in 10 of 10 papers, about 2.6 a paper. Aldehydes, Ketones and Carboxylic Acids alone had 22.

Chapter analysisStudy this chapterPractise this chapter

Aldehydes, Ketones and Carboxylic Acids: questions per paper

0242’171’181’192’204’214’223’234’243’253’26