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Friday, 9 October

JEE Main 2026 · ChemistryMultiple choiceSingle correctMediumApplication

JEE Main 2 April 2026, Shift 1, Chemistry Q57

Question 57 of 75 in this shift, Chemistry question 7 of 25, Section A.

An electrochemical cell is constructed using half cells in the direction of spontaneous change Fe(OH)2(s)+2e−→Fe(s)+2OH−(aq)\mathrm{Fe(OH)_2(s)+2e^-\rightarrow Fe(s)+2OH^-(aq)} Eθ=−0.88E^\theta=-0.88 V and AgBr(s)+e−→Ag(s)+Br−(aq)\mathrm{AgBr(s)+e^-\rightarrow Ag(s)+Br^-(aq)} Eθ=+0.07E^\theta=+0.07 V Which of the following option is correct ?
  1. (1)Overall reaction Fe(s)+2OH−(aq)+2AgBr(s)⇌Fe(OH)2(s)+2Ag(s)+2Br−(aq)\mathrm{Fe(s)+2OH^-(aq)+2AgBr(s)\rightleftharpoons Fe(OH)_2(s)+2Ag(s)+2Br^-(aq)}Official answer
  2. (2)Ecellθ=−0.95E^\theta_{cell}=-0.95 V
  3. (3)Fe is reduced in the electrochemical cell
  4. (4)EcellθE^\theta_{cell} is an extensive property

Official answer

Option 1

NTA final key.