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Friday, 9 October

JEE Main 2024 · ChemistryMultiple choiceSingle correctEasyConceptual

JEE Main 30 January 2024, Shift 2, Chemistry Q65

Question 65 of 90 in this shift, Chemistry question 5 of 30, Section A.

Reduction potential of ions are given below: ClO4−\mathrm{ClO_4^-} E∘=1.19 VE^\circ = 1.19\ V; IO4−\mathrm{IO_4^-} E∘=1.65 VE^\circ = 1.65\ V; BrO4−\mathrm{BrO_4^-} E∘=1.74 VE^\circ = 1.74\ V The correct order of their oxidising power is :
  1. (1)ClO4−>IO4−>BrO4−\mathrm{ClO_4^-} > \mathrm{IO_4^-} > \mathrm{BrO_4^-}
  2. (2)IO4−>BrO4−>ClO4−\mathrm{IO_4^-} > \mathrm{BrO_4^-} > \mathrm{ClO_4^-}
  3. (3)BrO4−>IO4−>ClO4−\mathrm{BrO_4^-} > \mathrm{IO_4^-} > \mathrm{ClO_4^-}Official answer
  4. (4)BrO4−>ClO4−>IO4−\mathrm{BrO_4^-} > \mathrm{ClO_4^-} > \mathrm{IO_4^-}

Official answer

Option 3

NTA final key.