The standard reduction potentials at 298 K for the following half cells are given below: $\mathrm{NO_3^- + 4H^+ + 3e^- \rightarrow NO(g) + 2H_2O}$ $E^\theta$ = 0.97 V $\mathrm{V^{2+}(aq) + 2e^- \rightarrow V}$ $E^\theta$ = $-1.19$ V $\mathrm{Fe^{3+}(aq) + 3e^- \rightarrow Fe}$ $E^\theta$ = $-0.04$ V $\mathrm{Ag^+(aq) + e^- \rightarrow Ag(s)}$ $E^\theta$ = 0.80 V $\mathrm{Au^{3+}(aq) + 3e^- \rightarrow Au(s)}$ $E^\theta$ = 1.40 V The number of metal(s) which will be oxidized by $\mathrm{NO_3^-}$ in aqueous solution is __________.

JEE Main 2023 · ChemistryNumerical answerNumerical valueMediumApplication

JEE Main 6 April 2023, Shift 2, Chemistry Q86

Question 86 of 90 in this shift, Chemistry question 26 of 30, Section B.

The standard reduction potentials at 298 K for the following half cells are given below:

\mathrm{NO_3^- + 4H^+ + 3e^- \rightarrow NO(g) + 2H_2O}

E^\theta

= 0.97 V

\mathrm{V^{2+}(aq) + 2e^- \rightarrow V}

E^\theta

-1.19

\mathrm{Fe^{3+}(aq) + 3e^- \rightarrow Fe}

E^\theta

-0.04

\mathrm{Ag^+(aq) + e^- \rightarrow Ag(s)}

E^\theta

= 0.80 V

\mathrm{Au^{3+}(aq) + 3e^- \rightarrow Au(s)}

E^\theta

= 1.40 V The number of metal(s) which will be oxidized by

\mathrm{NO_3^-}

in aqueous solution is __________.

Official answer

NTA final key.

Chapter: Electrochemistry
Topic: Nernst Equation
Idea tested: Standard Cell Potential

Same idea in other shifts

Asked 13× in all

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.