JEE Main 2026 (2 Apr, Shift 1) Chemistry Q56: Equilibrium

Question

The solubility product constants of $\mathrm{Ag_2CrO_4}$ and AgBr are $32x$ and $4y$ respectively at $298$ K.
The value of $\left(\frac{	ext{molarity of }\mathrm{Ag_2CrO_4}}{	ext{molarity of AgBr}}ight)$ can be expressed as :

Accepted Answer

Option 4: $\frac{\sqrt[3]{x}}{\sqrt{y}}$

Answer

$\frac{2\sqrt[3]{x}}{y}$

Answer

$2\sqrt{\frac{x}{y}}$

Answer

$\sqrt{\frac{x}{y}}$

Answer

$\frac{\sqrt[3]{x}}{\sqrt{y}}$

JEE Main 2 April 2026, Shift 1, Chemistry Q56

Same idea in other shifts