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Friday, 9 October

JEE Main 2020 · ChemistryNumerical answerNumerical valueEasyCalculation

JEE Main 6 September 2020, Shift 2, Chemistry Q47

Question 47 of 75 in this shift, Chemistry question 22 of 25.

If the solubility product of AB2\mathrm{AB_2} is 3.20×10−11 M33.20\times10^{-11}\ \mathrm{M^3}, then the solubility of AB2\mathrm{AB_2} in pure water is ________ ×10−4 mol L−1\times10^{-4}\ \mathrm{mol\,L^{-1}}. [Assuming that neither kind of ion reacts with water]

Official answer

2.00

NTA final key (Sep 2020).

Chapter
Equilibrium
Topic
Solubility Product
Idea tested
General Ksp Formula for AxBy Salts

Same idea in other shifts

Asked 2× in all
  1. 2 Apr 2026, Shift 1 · Q56The solubility product constants of Ag2CrO4\mathrm{Ag_2CrO_4} and AgBr are 32x32x and 4y4y respectively at 298298 K. The value of…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.