JEE Main 2020 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 6 September 2020, Shift 2, Chemistry Q48

Question 48 of 75 in this shift, Chemistry question 23 of 25.

The rate of a reaction decreased by 3.555 times when the temperature was changed from 40 °C to 30 °C. The activation energy (in kJ mol

^{-1}

) of the reaction is ________. Take; R = 8.314 J mol

^{-1}

^{-1}

, ln 3.555 = 1.268

Official answer

99.90 to 100.10

NTA final key (Sep 2020). Any value in the range scored.

Chapter: Chemical Kinetics
Topic: Arrhenius Equation
Idea tested: Two-Point Arrhenius Equation

Same idea in other shifts

Asked 5× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.