JEE Main 2026 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 2 April 2026, Shift 1, Chemistry Q74

Question 74 of 75 in this shift, Chemistry question 24 of 25, Section B.

For reaction

\mathrm{A\rightarrow P}

, rate constant

k=1.5\times10^3\ \mathrm{s^{-1}}

27^\circ

C If activation energy for the above reaction is

60\ \mathrm{kJ\ mol^{-1}}

, then the temperature (in

^\circ

C) at which rate constant,

k=4.5\times10^3\ \mathrm{s^{-1}}

is __________. (Nearest integer) Given :

\log2=0.30

\log3=0.48

R=8.3\ \mathrm{J\ K^{-1}\ mol^{-1}}

\ln10=2.3

Official answer

NTA final key.

Chapter: Chemical Kinetics
Topic: Arrhenius Equation
Idea tested: Two-Point Arrhenius Equation

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Asked 5× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.