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JEE Main 6 September 2020, Shift 2, Chemistry Q49

Question 49 of 75 in this shift, Chemistry question 24 of 25.

For Freundlich adsorption isotherm, a plot of

\log(x/m)

(

y

-axis) and

\log p

(

x

-axis) gives a straight line. The intercept and slope for the line is 0.4771 and 2, respectively. The mass of gas, adsorbed per gram of adsorbent if the initial pressure is 0.04 atm, is ________

\times10^{-4}

g. (

\log 3 = 0.4771

)

Official answer

48.00

NTA final key (Sep 2020).

Chapter: Surface Chemistry
Topic: Adsorption
Idea tested: Freundlich Logarithmic Plot

Same idea in other shifts

Asked 3× in all

3 Aug 2021, Shift 2 · Q58In an adsorption isotherm, it is seen that the graph of $\log\left(\frac{x}{m}\right)$ vs $\log P$ , where $P$ is in atm, is a straight…MediumNumerical value
2 Sep 2020, Shift 1 · Q48The mass of gas adsorbed, $x$ , per unit mass of adsorbate, $m$ , was measured at various pressures, $p$ . A graph between $\log\frac{x}{m}$ …MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.