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Friday, 9 October

JEE Main 2021 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 3 August 2021, Shift 2, Chemistry Q58

Question 58 of 90 in this shift, Chemistry question 28 of 30, Section B.

In an adsorption isotherm, it is seen that the graph of log⁡(xm)\log\left(\frac{x}{m}\right) vs log⁡P\log P, where PP is in atm, is a straight line inclined at 45∘45^\circ and the intercept is 0.699. The amount of solute in grams adsorbed per gram of adsorbent at a pressure of 0.5 atm is x×10−3x \times 10^{-3}. The value of xx is ‾\underline{\hspace{2em}}. (Nearest integer) [Use log⁡102=0.3010\log_{10} 2 = 0.3010 ; tan⁡45∘=1\tan 45^\circ = 1]

Official answer

398

NTA final key.

Chapter
Surface Chemistry
Topic
Adsorption
Idea tested
Freundlich Logarithmic Plot

Same idea in other shifts

Asked 3× in all
  1. 2 Sep 2020, Shift 1 · Q48The mass of gas adsorbed, xx, per unit mass of adsorbate, mm, was measured at various pressures, pp. A graph between log⁡xm\log\frac{x}{m}…MediumNumerical value
  2. 6 Sep 2020, Shift 2 · Q49For Freundlich adsorption isotherm, a plot of log⁡(x/m)\log(x/m) (yy-axis) and log⁡p\log p (xx-axis) gives a straight line. The intercept and…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.