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Friday, 9 October

JEE Main 2021 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 3 August 2021, Shift 2, Chemistry Q57

Question 57 of 90 in this shift, Chemistry question 27 of 30, Section B.

The inactivation process of virus is first order with respect to virus concentration and 2% of the virus was inactivated in the first one minute. Time taken (in minutes) for the virus to become 75% inactivated is ‾\underline{\hspace{2em}}. (Nearest integer) [Use log⁡102=0.3010\log_{10} 2 = 0.3010, log⁡103=0.4771\log_{10} 3 = 0.4771]

Official answer

69

NTA final key.