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Friday, 9 October

JEE Main 2021 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 3 August 2021, Shift 2, Chemistry Q56

Question 56 of 90 in this shift, Chemistry question 26 of 30, Section B.

The potential of a cell containing two hydrogen electrodes, one in contact with 10−810^{-8} M H+\mathrm{H^+} concentration and the other in contact with 0.025 M H+\mathrm{H^+} concentration is x×10−4x \times 10^{-4} V. The value of xx is ‾\underline{\hspace{2em}}. (Nearest integer) [Given : 2.303 RTF=0.059\frac{2.303\,RT}{F} = 0.059 and log⁡102=0.30\log_{10} 2 = 0.30]

Official answer

3776

NTA final key.

Chapter
Electrochemistry
Topic
Nernst Equation
Idea tested
Concentration Cells

Same idea in other shifts

Asked 2× in all
  1. 6 Sep 2020, Shift 2 · Q45For the given cell ; Cu(s)∣Cu2+(C1 M)∣∣Cu2+(C2 M)∣Cu(s)\mathrm{Cu(s)|Cu^{2+}(C_1\ M)||Cu^{2+}(C_2\ M)|Cu(s)} change in Gibbs energy (ΔG\Delta G) is negative, if :MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.