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Friday, 9 October

JEE Main 2024 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 30 January 2024, Shift 2, Physics Q60

Question 60 of 90 in this shift, Physics question 30 of 30, Section B.

A simple pendulum is placed at a place where its distance from the earth's surface is equal to the radius of the earth. If the length of the string is 4m4m, then the time period of small oscillations will be ________ ss. [take g=π2 ms−2g = \pi^2\ ms^{-2}]

Official answer

8

NTA final key.

Chapter
Oscillations
Topic
Pendulums
Idea tested
Pendulum of Comparable Length to Earth's Radius

Same topic in other shifts

All Pendulums questions
  1. 4 Apr 2026, Shift 2 · Q35A uniform disc of radius RR and mass MM is free to oscillate about the axis AA as shown in the figure. For small oscillations the time…MediumDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.