Learn

Friday, 9 October

JEE Main 2024 · ChemistryMultiple choiceSingle correctEasyRecall

JEE Main 30 January 2024, Shift 2, Chemistry Q61

Question 61 of 90 in this shift, Chemistry question 1 of 30, Section A.

If a substance 'A' dissolves in solution of a mixture of 'B' and 'C' with their respective number of moles as nA\mathrm{n_A}, nB\mathrm{n_B} and nC\mathrm{n_C}. Mole fraction of C in the solution is :
  1. (1)nBnA+nB\frac{\mathrm{n_B}}{\mathrm{n_A} + \mathrm{n_B}}
  2. (2)nCnA×nB×nC\frac{\mathrm{n_C}}{\mathrm{n_A} \times \mathrm{n_B} \times \mathrm{n_C}}
  3. (3)nCnA+nB+nC\frac{\mathrm{n_C}}{\mathrm{n_A} + \mathrm{n_B} + \mathrm{n_C}}Official answer
  4. (4)nCnA−nB−nC\frac{\mathrm{n_C}}{\mathrm{n_A} - \mathrm{n_B} - \mathrm{n_C}}

Official answer

Option 3

NTA final key.

Chapter
Solutions