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Saturday, 31 October

JEE Main 2024 · PhysicsMultiple choiceSingle correctMediumApplication

JEE Main 5 April 2024, Shift 1, Physics Q40

Question 40 of 90 in this shift, Physics question 10 of 30, Section A.

A simple pendulum doing small oscillations at a place R height above earth surface has time period of T1=4T_1 = 4 s. T2T_2 would be it's time period if it is brought to a point which is at a height 2R from earth surface. Choose the correct relation [R = radius of earth] :
  1. (1)T1=T2T_1 = T_2
  2. (2)2T1=T22T_1 = T_2
  3. (3)3T1=2T23T_1 = 2T_2Official answer
  4. (4)2T1=3T22T_1 = 3T_2

Official answer

Option 3

NTA final key.

Chapter
Gravitation
Topic
Pendulums
Idea tested
Period Variation with Altitude and Depth

Same idea in other shifts

Asked 2× in all
  1. 1 Feb 2024, Shift 1 · Q36If R is the radius of the earth and the acceleration due to gravity on the surface of earth is g = π2\pi^2 m/s2^2, then the length of the…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.