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JEE Main 2024 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 1 February 2024, Shift 1, Physics Q36

Question 36 of 90 in this shift, Physics question 6 of 30, Section A.

If R is the radius of the earth and the acceleration due to gravity on the surface of earth is g =

\pi^2

m/s

^2

, then the length of the second's pendulum at a height h = 2R from the surface of earth will be, :

(1) $\frac{2}{9}$ m
(2) $\frac{4}{9}$ m
(3) $\frac{8}{9}$ m
(4) $\frac{1}{9}$ mOfficial answer

Official answer

Option 4

NTA final key.

Chapter: Gravitation
Topic: Pendulums
Idea tested: Period Variation with Altitude and Depth

Same idea in other shifts

Asked 2× in all

5 Apr 2024, Shift 1 · Q40A simple pendulum doing small oscillations at a place R height above earth surface has time period of $T_1 = 4$ s. $T_2$ would be it's…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.