JEE Main 2022 · PhysicsMultiple choiceSingle correctEasyConceptual

JEE Main 28 June 2022, Shift 1, Physics Q33

Question 33 of 90 in this shift, Physics question 3 of 30, Section A.

Motion of a particle in

x

y

plane is described by a set of following equations

x = 4\sin\left(\frac{\pi}{2}-\omega t\right)

m and

y = 4\sin(\omega t)

m. The path of the particle will be :

(1)circularOfficial answer
(2)helical
(3)parabolic
(4)elliptical

Official answer

Option 1

NTA final key.

Chapter: Oscillations
Topic: SHM Equations
Idea tested: Perpendicular Superposition (Lissajous)

Same topic in other shifts

All SHM Equations questions

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2 Apr 2025, Shift 1 · Q33A particle is subjected to two simple harmonic motions as : $x_1=\sqrt{7}\sin5t$ cm and $x_2=2\sqrt{7}\sin\left(5t+\frac{\pi}{3}\right)$ …MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.