JEE Main 2026 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 2 April 2026, Shift 2, Physics Q45

Question 45 of 75 in this shift, Physics question 20 of 25, Section A.

The equation of motion of a particle is given by

x = a\sin\left(50t + \frac{\pi}{3}\right)

cm. The particle will come to rest at time

t_1

and it will have zero acceleration at time

t_2

. The

t_1

and

t_2

respectively are

(1) $\frac{\pi}{300}$ s, $\frac{\pi}{75}$ sOfficial answer
(2) $\frac{\pi}{75}$ s, $\frac{\pi}{300}$ s
(3) $\frac{\pi}{300}$ s, $\frac{\pi}{25}$ s
(4) $\frac{\pi}{50}$ s, $\frac{\pi}{100}$ s

Official answer

Option 1

NTA final key.

Chapter: Oscillations
Topic: SHM Equations
Idea tested: Velocity and Accel vs Time

Same topic in other shifts

All SHM Equations questions

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.