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Friday, 9 October

JEE Main 2026 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 6 April 2026, Shift 1, Physics Q37

Question 37 of 75 in this shift, Physics question 12 of 25, Section A.

A particle is executing simple harmonic motion. Its amplitude is AA and time period is 5 sec. The time required by it to move from x=Ax=A to x=A2x=\frac{A}{\sqrt{2}} is ________ sec.
  1. (1)1/4
  2. (2)5/4
  3. (3)5/8Official answer
  4. (4)3/8

Official answer

Option 3

NTA final key.