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JEE Main 2026 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 6 April 2026, Shift 1, Physics Q38

Question 38 of 75 in this shift, Physics question 13 of 25, Section A.

A thin half ring of radius 35 cm is uniformly charged with a total charge of

Q

coulomb. If the magnitude of the electric field at centre of the half ring is 100 V/m, then the value of

Q

is ________ nC. (

\epsilon_0=8.85\times10^{-12}

C

^2

/Nm

^2

and

\pi=3.14

)

(1)2.14Official answer
(2)2.44
(3)3.25
(4)0.7

Official answer

Option 1

NTA final key.

Chapter: Electric Charges and Fields
Topic: Electric Field
Idea tested: Charged Arc Field

Same idea in other shifts

Asked 2× in all

4 Apr 2025, Shift 2 · Q38A metallic ring is uniformly charged as shown in figure. AC and BD are two mutually perpendicular diameters. Electric field due to arc AB…MediumDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.