JEE Main 2025 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 2 April 2025, Shift 1, Physics Q33

Question 33 of 75 in this shift, Physics question 8 of 25, Section A.

A particle is subjected to two simple harmonic motions as :

x_1=\sqrt{7}\sin5t

cm and

x_2=2\sqrt{7}\sin\left(5t+\frac{\pi}{3}\right)

cm where

x

is displacement and

t

is time in seconds. The maximum acceleration of the particle is

x\times10^{-2}\ \mathrm{ms^{-2}}

. The value of

x

is :

(1) $25\sqrt{7}$
(2) $5\sqrt{7}$
(3)125
(4)175Official answer

Official answer

Option 4

NTA final key.

Chapter: Oscillations
Topic: SHM Equations
Idea tested: Collinear Superposition of SHMs

Same topic in other shifts

All SHM Equations questions

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8 Apr 2026, Shift 2 · Q37The frequency of oscillation of a mass $m$ suspended by a spring is $v_1$ . If the length of the spring is cut to half, the same mass…EasySingle correct
3 Apr 2025, Shift 1 · Q36Two blocks of masses m and M, $(M > m)$ , are placed on a frictionless table as shown in figure. A massless spring with spring constant k…HardOtherHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.