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Saturday, 31 October

JEE Main 2022 · ChemistryNumerical answerNumerical valueEasyCalculation

JEE Main 27 July 2022, Shift 1, Chemistry Q90

Question 90 of 90 in this shift, Chemistry question 30 of 30, Section B.

In the following reaction [figure: benzene →Oleum\xrightarrow{\text{Oleum}} (I) benzene bearing SO3H\mathrm{SO_3H} →NaOH (excess)/H+\xrightarrow{\text{NaOH (excess)/H}^+} (II) benzene bearing OH] The % yield for reaction I is 60% and that of reaction II is 50%. The overall yield of the complete reaction is __%. [nearest integer]

The figure, in words

Three benzene rings (hexagon with alternating double bonds) in a row: plain benzene, then arrow labelled Oleum (I) to benzene with SO3H at the top, then arrow labelled NaOH (excess) over H+ (II) to benzene with OH at the top.

Official answer

30

NTA final key.