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Friday, 9 October

JEE Main 2026 · ChemistryNumerical answerNumerical valueEasyCalculation

JEE Main 4 April 2026, Shift 2, Chemistry Q75

Question 75 of 75 in this shift, Chemistry question 25 of 25, Section B.

In sulphur estimation, 2.0×10−32.0\times10^{-3} mol of an organic compound (X) (molar mass 76 g mol−1\mathrm{g\ mol^{-1}}) gave 0.4813 g of barium sulphate (molar mass 233 g mol−1\mathrm{g\ mol^{-1}}). The percentage of sulphur in the compound (X) is ________ ×10−1\times10^{-1} % (Nearest integer)

Official answer

435

NTA final key.