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Friday, 9 October

JEE Main 2026 · ChemistryMultiple choiceSingle correctMediumCalculation

JEE Main 2 April 2026, Shift 2, Chemistry Q62

Question 62 of 75 in this shift, Chemistry question 12 of 25, Section A.

Complete combustion of X g of an organic compound gave 0.25 g of CO2CO_2 and 0.12 g of H2OH_2O. If the % of carbon is 25% and of hydrogen is 4.89%, then X=‾×10−3X = \underline{\hspace{1cm}} \times 10^{-3} g. (Nearest integer) (Molar mass of C, H and O are 12, 1 and 16 g mol−1^{-1} respectively.)
  1. (1)273273Official answer
  2. (2)2727
  3. (3)27302730
  4. (4)227227

Official answer

Option 1

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 7 Apr 2025, Shift 1 · Q74An organic compound weighing 500 mg, produced 220 mg of CO2\mathrm{CO_2}, on complete combustion. The percentage composition of carbon in…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.