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Friday, 9 October

JEE Main 2020 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 6 September 2020, Shift 2, Physics Q5

Question 5 of 75 in this shift, Physics question 5 of 25.

The linear mass density of a thin rod AB of length L varies from A to B as λ(x)=λ0(1+xL)\lambda(x)=\lambda_0\left(1+\frac{x}{L}\right), where xx is the distance from A. If M is the mass of the rod then its moment of inertia about an axis passing through A and perpendicular to the rod is :
  1. (1)512ML2\frac{5}{12}ML^2
  2. (2)718ML2\frac{7}{18}ML^2Official answer
  3. (3)25ML2\frac{2}{5}ML^2
  4. (4)37ML2\frac{3}{7}ML^2

Official answer

Option 2

NTA final key (Sep 2020).