JEE Main 2025 · PhysicsMultiple choiceSingle correctEasyApplication

JEE Main 2 April 2025, Shift 2, Physics Q28

Question 28 of 75 in this shift, Physics question 3 of 25, Section A.

The moment of inertia of a circular ring of mass

M

and diameter

r

about a tangential axis lying in the plane of the ring is :

(1) $2Mr^2$
(2) $\frac{3}{2}Mr^2$
(3) $\frac{3}{8}Mr^2$ Official answer
(4) $\frac{1}{2}Mr^2$

Official answer

Option 3

NTA final key.

Chapter: System of Particles and Rotational Motion
Topic: Moment of Inertia
Idea tested: MOI of a Ring About Tangents

Same topic in other shifts

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.