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Friday, 9 October

JEE Main 2026 · PhysicsNumerical answerNumerical valueMediumMulti-step

JEE Main 2 April 2026, Shift 2, Physics Q50

Question 50 of 75 in this shift, Physics question 25 of 25, Section B.

Moment of inertia about an axis ABAB for a rod of mass 40 kg and length 3 m is same as that of a solid sphere of mass of 10 kg and radius RR about an axis parallel to ABAB axis with separation of 3 m as shown in figure below. The value of RR is given as α2\sqrt{\frac{\alpha}{2}}. The value of α\alpha is

The figure, in words

[figure: rod of length 3m and mass M=40kg above a sphere of radius R and mass 10kg, with vertical distance of 3m between rod and sphere]

Official answer

60

NTA final key.

Chapter
System of Particles and Rotational Motion
Topic
Moment of Inertia
Idea tested
Parallel Axis Theorem

Same idea in other shifts

Asked 2× in all
  1. 31 Jan 2024, Shift 2 · Q52Two identical spheres each of mass 2 kg and radius 50 cm are fixed at the ends of a light rod so that the separation between the centers…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.