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Friday, 9 October

JEE Main 2024 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 31 January 2024, Shift 2, Physics Q52

Question 52 of 90 in this shift, Physics question 22 of 30, Section B.

Two identical spheres each of mass 2 kg and radius 50 cm are fixed at the ends of a light rod so that the separation between the centers is 150 cm. Then, moment of inertia of the system about an axis perpendicular to the rod and passing through its middle point is x20\frac{x}{20} kg m2^2, where the value of xx is __________.

Official answer

53

NTA final key.

Chapter
System of Particles and Rotational Motion
Topic
Moment of Inertia
Idea tested
Parallel Axis Theorem

Same idea in other shifts

Asked 2× in all
  1. 2 Apr 2026, Shift 2 · Q50Moment of inertia about an axis ABAB for a rod of mass 40 kg and length 3 m is same as that of a solid sphere of mass of 10 kg and radius…MediumNumerical valueHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.