JEE Main 2020 (6 Sep, Shift 2) Physics Q4: Collisions

Question

Particle A of mass

m_1

moving with velocity

\left(\sqrt{3}\hat{i}+\hat{j}\right)\,\mathrm{ms^{-1}}

collides with another particle B of mass

m_2

which is at rest initially. Let

\vec{V_1}

and

\vec{V_2}

be the velocities of particles A and B after collision respectively. If

m_1 = 2m_2

and after collision

\vec{V_1} = \left(\hat{i}+\sqrt{3}\hat{j}\right)\,\mathrm{ms^{-1}}

, the angle between

\vec{V_1}

and

\vec{V_2}

is :

Official answer

Option 3

NTA final key (Sep 2020).

Accepted Answer

Option 3: $105^\circ$

Answer

$-45^\circ$

Answer

$60^\circ$

Answer

$105^\circ$

Answer

$15^\circ$

JEE Main 6 September 2020, Shift 2, Physics Q4