JEE Main 2020 · ChemistryMultiple choiceSingle correctEasyCalculation
JEE Main 6 September 2020, Shift 2, Chemistry Q44
Question 44 of 75 in this shift, Chemistry question 19 of 25.
The value of is 64 at 800 K for the reaction
The value of for the following reaction is :
- (1)1/64
- (2)8
- (3)1/8Official answer
- (4)1/4
Official answer
Option 3
NTA final key (Sep 2020).
- Chapter
- Equilibrium
- Topic
- Chemical Equilibrium
- Idea tested
- Equilibrium Constant for Modified Equations