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JEE Main 26 July 2022, Shift 1, Chemistry Q86

Question 86 of 90 in this shift, Chemistry question 26 of 30, Section B.

At 298 K, the equilibrium constant is

2 \times 10^{15}

for the reaction :

\mathrm{Cu(s)} + 2\mathrm{Ag^+(aq)} \rightleftharpoons \mathrm{Cu^{2+}(aq)} + 2\mathrm{Ag(s)}

The equilibrium constant for the reaction

\frac{1}{2}\mathrm{Cu^{2+}(aq)} + \mathrm{Ag(s)} \rightleftharpoons \frac{1}{2}\mathrm{Cu(s)} + \mathrm{Ag^+(aq)}

x \times 10^{-8}

. The value of

x

is __________. (Nearest Integer)

Official answer

NTA final key.

Chapter: Equilibrium
Topic: Chemical Equilibrium
Idea tested: Equilibrium Constant for Modified Equations

Same idea in other shifts

Asked 9× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.