JEE Main 2024 · ChemistryMultiple choiceSingle correctEasyCalculation

JEE Main 8 April 2024, Shift 1, Chemistry Q63

Question 63 of 90 in this shift, Chemistry question 3 of 30, Section A.

For the given hypothetical reactions, the equilibrium constants are as follows :

\mathrm{X\rightleftharpoons Y}

;

K_1=1.0

\mathrm{Y\rightleftharpoons Z}

;

K_2=2.0

\mathrm{Z\rightleftharpoons W}

;

K_3=4.0

The equilibrium constant for the reaction

\mathrm{X\rightleftharpoons W}

(1) $7.0$
(2) $8.0$ Official answer
(3) $12.0$
(4) $6.0$

Official answer

Option 2

NTA final key.

Chapter: Equilibrium
Topic: Chemical Equilibrium
Idea tested: Equilibrium Constant for Modified Equations

Same idea in other shifts

Asked 4× in all

4 Apr 2026, Shift 1 · Q55At T(K), the equilibrium constant of $\mathrm{A_2}(g)+\mathrm{B_2}(g)\rightleftharpoons \mathrm{C}(g)$ is $2.7\times10^{-5}$ . What is the…EasySingle correct
8 Apr 2026, Shift 2 · Q55Consider the following reactions in which all the reactants and products are present in gaseous state $2\,xy \rightleftharpoons x_2 + y_2$ …MediumSingle correct
6 Sep 2020, Shift 2 · Q44The value of $\mathrm{K_c}$ is 64 at 800 K for the reaction $\mathrm{N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)}$ The value of…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.