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Friday, 9 October

JEE Main 2020 · ChemistryMultiple choiceSingle correctEasyApplication

JEE Main 6 September 2020, Shift 2, Chemistry Q43

Question 43 of 75 in this shift, Chemistry question 18 of 25.

A set of solutions is prepared using 180 g of water as a solvent and 10 g of different non-volatile solutes A, B and C. The relative lowering of vapour pressure in the presence of these solutes are in the order [Given, molar mass of A = 100 g mol−1^{-1}; B = 200 g mol−1^{-1}; C = 10,000 g mol−1^{-1}]
  1. (1)A>B>CA>B>COfficial answer
  2. (2)B>C>AB>C>A
  3. (3)C>B>AC>B>A
  4. (4)A>C>BA>C>B

Official answer

Option 1

NTA final key (Sep 2020).

Chapter
Solutions