NEET UG 2024 · Chemistry · Question 98
NEET 2024 Chemistry, question 98
Question 98 of the NEET 2024 paper (code T2) is a Chemistry question from Haloalkanes and Haloarenes. Its idea, Aqueous vs Alcoholic KOH, was asked only this once in NEET 2017–2026. The NTA final answer key gives option 3.
Updated 2026-10-08
Q98 · Chemistry
Major products A and B formed in the following reaction sequence, are
[2-methylcyclohexan-1-ol] A (major) B (major)
The figure, described in words
Reactant drawn: 2-methylcyclohexan-1-ol; option structures as described in the options.
- 1[structures: A = 2-bromo-6-methylcyclohexan-1-ol; B = 6-methylcyclohex-2-en-1-ol]
- 2[structures: A = 2-bromo-6-methylcyclohexan-1-ol; B = 2-methylcyclohexan-1-one]
- 3[structures: A = 1-bromo-2-methylcyclohexane; B = 1-methylcyclohexene]Official answer
- 4[structures: A = 1-bromo-2-methylcyclohexane; B = methylcyclohexene with the C=C not at the methyl-bearing carbon]
Official answer: option 3 · NTA final answer key
Same idea
The only question on Aqueous vs Alcoholic KOH
No other NEET paper from 2017–2026 tested this exact idea.
Aqueous vs Alcoholic KOH: every question and how it was framed
The chapter
Haloalkanes and Haloarenes in ten years of NEET
16 questions from 2017–2026, asked in 10 of 10 papers, about 1.5 a paper. Nucleophilic Substitution alone had 16.