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Saturday, 10 October

NEET UG 2024 · Chemistry · Question 95

NEET 2024 Chemistry, question 95

Question 95 of the NEET 2024 paper (code T2) is a Chemistry question from Equilibrium. Its idea, Degree of Dissociation and Equilibrium Constant, was asked only this once in NEET 2017–2026. The NTA final answer key gives option 2.

Updated 2026-10-08

Q95 · Chemistry

Consider the following reaction in a sealed vessel at equilibrium with concentrations of N2_2 = 3.0×10−33.0\times10^{-3} M, O2_2 = 4.2×10−34.2\times10^{-3} M and NO = 2.8×10−32.8\times10^{-3} M.

2NO(g)_{(g)} ⇌\rightleftharpoons N2(g)_{2(g)} + O2(g)_{2(g)}

If 0.1 mol L−1^{-1} of NO(g)_{(g)} is taken in a closed vessel, what will be degree of dissociation (α\alpha) of NO(g)_{(g)} at equilibrium?

  1. 10.8889
  2. 20.717Official answer
  3. 30.00889
  4. 40.0889

Official answer: option 2 · NTA final answer key

Same idea

The only question on Degree of Dissociation and Equilibrium Constant

No other NEET paper from 2017–2026 tested this exact idea.

Degree of Dissociation and Equilibrium Constant: every question and how it was framed

The chapter

Equilibrium in ten years of NEET

26 questions from 2017–2026, asked in 10 of 10 papers, about 2.5 a paper. Chemical Equilibrium alone had 11.

Equilibrium: questions per paper

0363’173’183’192’201’212’222’235’244’251’26