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Friday, 9 October

NEET UG 2024 · Chemistry · Question 57

NEET 2024 Chemistry, question 57

Question 57 of the NEET 2024 paper (code T2) is a Chemistry question from Structure of Atom. Its idea, Single-Electron Species Energy Exception, was asked 3 times, in 2024 and 2025, across NEET 2017–2026. The NTA final answer key gives option 3.

Updated 2026-10-08

Q57 · Chemistry

The energy of an electron in the ground state (n = 1) for He+^+ ion is −x-x J, then that for an electron in n = 2 state for Be3+^{3+} ion in J is :

  1. 1−4x-4x
  2. 2−49x-\frac{4}{9}x
  3. 3−x-xOfficial answer
  4. 4−x9-\frac{x}{9}

Official answer: option 3 · NTA final answer key

Same idea

Single-Electron Species Energy Exception, in other papers

NEET asked this idea 3 times, in 2024 and 2025. The other 2 questions below.

  • 2025 Q46The ratio of the wavelengths of the light absorbed by a Hydrogen atom when it undergoes n=2→n=3n = 2 \to n = 3 and n=4→n=6n = 4 \to n = 6…Numerical · Medium
  • 2025 Q50Energy and radius of first Bohr orbit of He+He^+ and Li2+Li^{2+} are [Given RH=2.18×10−18R_H = 2.18\times10^{-18} J, a0a_0 = 52.9 pm]Numerical · Medium

Single-Electron Species Energy Exception: every question and how it was framed

The chapter

Structure of Atom in ten years of NEET

16 questions from 2017–2026, asked in 10 of 10 papers, about 1.5 a paper. Quantum Numbers alone had 16.

Chapter analysisStudy this chapterPractise this chapter

Structure of Atom: questions per paper

0241’171’182’191’202’212’222’232’242’251’26