NEET UG 2024 · Physics · Question 50
NEET 2024 Physics, question 50
Question 50 of the NEET 2024 paper (code T2) is a Physics question from Alternating Current. Its idea, Capacitive Reactance Calculation, was asked twice, in 2020 and 2024, across NEET 2017–2026. The NTA final answer key gives option 4.
Updated 2026-10-08
Q50 · Physics
A 10 F capacitor is connected to a 210 V, 50 Hz source as shown in figure. The peak current in the circuit is nearly ():
The figure, described in words
Circuit: a 10 μF capacitor connected across a 210 V, 50 Hz AC source.
- 11.20 A
- 20.35 A
- 30.58 A
- 40.93 AOfficial answer
Official answer: option 4 · NTA final answer key
Same idea
Capacitive Reactance Calculation, in other papers
NEET asked this idea twice, in 2020 and 2024. The other question below.
- 2020 Q154A 40 F capacitor is connected to a 200 V, 50 Hz ac supply. The rms value of the current in the circuit is, nearly :Numerical · Easy
Capacitive Reactance Calculation: every question and how it was framed
The chapter
Alternating Current in ten years of NEET
15 questions from 2017–2026, asked in 8 of 10 papers, about 1.4 a paper. LCR Circuits alone had 15.