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Saturday, 10 October

NEET UG 2019 · Chemistry · Question 47

NEET 2019 Chemistry, question 47

Question 47 of the NEET 2019 paper (code P1) is a Chemistry question from Alcohols, Phenols and Ethers. Its idea, Cumene Process, was asked twice, in 2018 and 2019, across NEET 2017–2026. The NTA final answer key gives option 2.

Updated 2026-10-08

Q47 · Chemistry

The structure of intermediate A in the following reaction, is :

C₆H₅–CH(CH₃)₂ (cumene) →O2\xrightarrow{O_2} A →H+,H2O\xrightarrow{H^+, H_2O} C₆H₅OH (phenol) + CH₃COCH₃ (acetone)

The figure, described in words

Reaction scheme drawn with structures: cumene oxidised by O2 to A, which with H+/H2O gives phenol and acetone; options are drawn structures.

  1. 1[structure: C₆H₅–O–CH(CH₃)₂]
  2. 2[structure: C₆H₅–C(CH₃)₂–O–O–H]Official answer
  3. 3[structure: C₆H₅–O–O–CH(CH₃)₂]
  4. 4[structure: C₆H₅–CH(CH₃)–CH₂–O–O–H]

Official answer: option 2 · NTA final answer key

Same idea

Cumene Process, in other papers

NEET asked this idea twice, in 2018 and 2019. The other question below.

  • 2018 Q52Identify the major products P, Q and R in the following sequence of reactions : Benzene + CH3CH2CH2Cl\mathrm{CH_3CH_2CH_2Cl}…Other · Medium

Cumene Process: every question and how it was framed

The chapter

Alcohols, Phenols and Ethers in ten years of NEET

15 questions from 2017–2026, asked in 7 of 10 papers, about 1.4 a paper. Alcohols and Phenols alone had 15.

Alcohols, Phenols and Ethers: questions per paper

0242’174’182’192’200’212’222’231’240’250’26