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Saturday, 10 October

JEE Main Maths · Sequences and Series

Method of Differences for Telescoping Series

Method of Differences for Telescoping Series (Sequences and Series) was asked 8 times in 8 JEE Main shifts, 2021–2026, out of the 42 shifts Lumi analysed. 1 of the 8 had a numerical answer.

Times asked
8
in 8 shifts
Years
2021–2026
Usual format
Single correct
Calculation
Pattern
Asked most years
repeats across shifts

How it is asked

  • Sum of series with summation general term
  • Sum of telescoping series

Difficulty

Easy 1Medium 6Hard 1

Where it sits

Chapter: Sequences and Series. Topic: AP and GP, 59 questions over 17 ideas.

Other repeat ideas in this topic

Every time it came

All 8 questions

Newest first, each with its options and official answer.

  1. 5 Apr 2026, Shift 1 · Q5∑n=110(528n(n+1)(n+2))\sum_{n=1}^{10}\left(\frac{528}{n(n+1)(n+2)}\right) is equal to:EasySingle correct
  2. 3 Apr 2025, Shift 1 · Q7The sum 1+3+11+25+45+71+…1 + 3 + 11 + 25 + 45 + 71 + \ldots upto 20 terms, is equal toMediumSingle correct
  3. 4 Apr 2025, Shift 2 · Q5If the sum of the first 20 terms of the series…MediumSingle correct
  4. 9 Apr 2024, Shift 2 · Q24If…HardNumerical value
  5. 31 Jan 2024, Shift 1 · Q5The sum of the series 11−3⋅12+14+21−3⋅22+24+31−3⋅32+34+…\frac{1}{1-3\cdot1^2+1^4}+\frac{2}{1-3\cdot2^2+2^4}+\frac{3}{1-3\cdot3^2+3^4}+\ldots up to 10-terms isMediumSingle correct
  6. 6 Apr 2023, Shift 1 · Q7The sum of the first 20 terms of the series 5+11+19+29+41+…5+11+19+29+41+\ldots isMediumSingle correct
  7. 8 Apr 2023, Shift 2 · Q8Let ana_n be the nthn^{th} term of the series 5+8+14+23+35+50+…5 + 8 + 14 + 23 + 35 + 50 + \ldots and Sn=∑k=1nakS_n = \sum_{k=1}^{n} a_k. Then S30−a40S_{30} - a_{40}…MediumSingle correct
  8. 18 Mar 2021, Shift 1 · Q68132−1+152−1+172−1+…+1(201)2−1\frac{1}{3^2-1}+\frac{1}{5^2-1}+\frac{1}{7^2-1}+\ldots+\frac{1}{(201)^2-1} is equal to :MediumSingle correct