JEE Main 2026 · MathsMultiple choiceSingle correctEasyCalculation

JEE Main 6 April 2026, Shift 2, Maths Q14

Question 14 of 75 in this shift, Maths question 14 of 25, Section A.

The shortest distance between the lines

\frac{x-4}{1}=\frac{y-3}{2}=\frac{z-2}{-3}

and

\frac{x+2}{2}=\frac{y-6}{4}=\frac{z-5}{-5}

is :

(1) $\frac{5\sqrt{6}}{6}$
(2) $2\sqrt{5}$
(3) $3\sqrt{5}$ Official answer
(4) $4\sqrt{5}$

Official answer

Option 3

NTA final key.

Chapter: Three Dimensional Geometry
Topic: Skew Lines
Idea tested: Cartesian Shortest Distance

Same idea in other shifts

Asked 5× in all

7 Apr 2025, Shift 1 · Q14If the shortest distance between the lines $\frac{x-1}{2} = \frac{y-2}{3} = \frac{z-3}{4}$ and…MediumSingle correct
9 Apr 2024, Shift 1 · Q16The shortest distance between the lines $\frac{x-3}{4}=\frac{y+7}{-11}=\frac{z-1}{5}$ and $\frac{x-5}{3}=\frac{y-9}{-6}=\frac{z+2}{1}$ is :EasySingle correct
31 Jan 2024, Shift 2 · Q17The shortest distance, between lines $L_1$ and $L_2$ , where $L_1:\frac{x-1}{2}=\frac{y+1}{-3}=\frac{z+4}{2}$ and $L_2$ is the line,…MediumSingle correct
8 Jan 2020, Shift 1 · Q65The shortest distance between the lines $\dfrac{x-3}{3}=\dfrac{y-8}{-1}=\dfrac{z-3}{1}$ and…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.