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Friday, 9 October

JEE Main 2025 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 7 April 2025, Shift 1, Maths Q14

Question 14 of 75 in this shift, Maths question 14 of 25, Section A.

If the shortest distance between the lines x−12=y−23=z−34\frac{x-1}{2} = \frac{y-2}{3} = \frac{z-3}{4} and x1=yα=z−51\frac{x}{1} = \frac{y}{\alpha} = \frac{z-5}{1} is 56\frac{5}{\sqrt{6}}, then the sum of all possible values of α\alpha is
  1. (1)33
  2. (2)−3-3Official answer
  3. (3)32\frac{3}{2}
  4. (4)−32-\frac{3}{2}

Official answer

Option 2

NTA final key.