JEE Main 2024 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 31 January 2024, Shift 2, Maths Q17

Question 17 of 90 in this shift, Maths question 17 of 30, Section A.

The shortest distance, between lines

L_1

and

L_2

, where

L_1:\frac{x-1}{2}=\frac{y+1}{-3}=\frac{z+4}{2}

and

L_2

is the line, passing through the points

A(-4,4,3)

B(-1,6,3)

and perpendicular to the line

\frac{x-3}{-2}=\frac{y}{3}=\frac{z-1}{1}

, is

(1) $\frac{24}{\sqrt{117}}$
(2) $\frac{42}{\sqrt{117}}$
(3) $\frac{121}{\sqrt{221}}$
(4) $\frac{141}{\sqrt{221}}$ Official answer

Official answer

Option 4

NTA final key.

Chapter: Three Dimensional Geometry
Topic: Skew Lines
Idea tested: Cartesian Shortest Distance

Same idea in other shifts

Asked 5× in all

6 Apr 2026, Shift 2 · Q14The shortest distance between the lines $\frac{x-4}{1}=\frac{y-3}{2}=\frac{z-2}{-3}$ and $\frac{x+2}{2}=\frac{y-6}{4}=\frac{z-5}{-5}$ is :EasySingle correct
7 Apr 2025, Shift 1 · Q14If the shortest distance between the lines $\frac{x-1}{2} = \frac{y-2}{3} = \frac{z-3}{4}$ and…MediumSingle correct
9 Apr 2024, Shift 1 · Q16The shortest distance between the lines $\frac{x-3}{4}=\frac{y+7}{-11}=\frac{z-1}{5}$ and $\frac{x-5}{3}=\frac{y-9}{-6}=\frac{z+2}{1}$ is :EasySingle correct
8 Jan 2020, Shift 1 · Q65The shortest distance between the lines $\dfrac{x-3}{3}=\dfrac{y-8}{-1}=\dfrac{z-3}{1}$ and…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.