JEE Main 2026 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 5 April 2026, Shift 2, Maths Q5

Question 5 of 75 in this shift, Maths question 5 of 25, Section A.

If the sum of the first 10 terms of the series

\frac{1}{1+1^4\times 4}+\frac{2}{1+2^4\times 4}+\frac{3}{1+3^4\times 4}+\frac{4}{1+4^4\times 4}+\dots\dots

\frac{m}{n}

\gcd(m, n)=1

, then

m+n

is equal to :

(1) $256$
(2) $264$
(3) $276$ Official answer
(4) $284$

Official answer

Option 3

NTA final key.

Chapter: Sequences and Series
Topic: AP and GP
Idea tested: Method of Differences (Vn Method)

Same idea in other shifts

Asked 4× in all

2 Apr 2025, Shift 2 · Q22If the sum of the first 10 terms of the series…HardNumerical value
9 Apr 2024, Shift 1 · Q5If the sum of the series $\frac{1}{1\cdot(1+d)}+\frac{1}{(1+d)(1+2d)}+\ldots+\frac{1}{(1+9d)(1+10d)}$ is equal to $5$ , then $50d$ is equal…MediumSingle correct
6 Apr 2023, Shift 1 · Q8Let $a_1,a_2,a_3,\ldots,a_n$ be $n$ positive consecutive terms of an arithmetic progression. If $d>0$ is its common difference, then…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.