JEE Main 2025 · MathsNumerical answerNumerical valueHardCalculation

JEE Main 2 April 2025, Shift 2, Maths Q22

Question 22 of 75 in this shift, Maths question 22 of 25, Section B.

If the sum of the first 10 terms of the series

\frac{4\cdot1}{1+4\cdot1^4} + \frac{4\cdot2}{1+4\cdot2^4} + \frac{4\cdot3}{1+4\cdot3^4} + \ldots

\frac{m}{n}

, where

\gcd(m, n) = 1

, then

m + n

is equal to __________.

Official answer

441

NTA final key.

Chapter: Sequences and Series
Topic: AP and GP
Idea tested: Method of Differences (Vn Method)

Same idea in other shifts

Asked 4× in all

5 Apr 2026, Shift 2 · Q5If the sum of the first 10 terms of the series…HardSingle correct
9 Apr 2024, Shift 1 · Q5If the sum of the series $\frac{1}{1\cdot(1+d)}+\frac{1}{(1+d)(1+2d)}+\ldots+\frac{1}{(1+9d)(1+10d)}$ is equal to $5$ , then $50d$ is equal…MediumSingle correct
6 Apr 2023, Shift 1 · Q8Let $a_1,a_2,a_3,\ldots,a_n$ be $n$ positive consecutive terms of an arithmetic progression. If $d>0$ is its common difference, then…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.