JEE Main 2 April 2025, Shift 2, Maths Q23

Question 23 of 75 in this shift, Maths question 23 of 25, Section B.

y = \cos\left(\frac{\pi}{3} + \cos^{-1}\frac{x}{2}\right)

, then

(x-y)^2 + 3y^2

is equal to __________.

Official answer

NTA final key.

Chapter: Inverse Trigonometric Functions
Topic: Inverse Trig Identities
Idea tested: Trig of Sum of Inverse Trig Functions

Same idea in other shifts

Asked 2× in all

29 Jun 2022, Shift 1 · Q26…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.