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Saturday, 31 October

JEE Main 2022 · MathsMultiple choiceSingle correctEasyCalculation

JEE Main 30 June 2022, Shift 1, Maths Q7

Question 7 of 90 in this shift, Maths question 7 of 30, Section A.

The value of 1+11+2+11+2+3+…+11+2+3+…+111 + \frac{1}{1+2} + \frac{1}{1+2+3} + \ldots + \frac{1}{1+2+3+\ldots+11} is equal to :
  1. (1)2011\frac{20}{11}
  2. (2)116\frac{11}{6}Official answer
  3. (3)241132\frac{241}{132}
  4. (4)2111\frac{21}{11}

Official answer

Option 2

NTA final key.