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Friday, 9 October

JEE Main 2026 · ChemistryMultiple choiceOtherMediumConceptual

JEE Main 5 April 2026, Shift 1, Chemistry Q65

Question 65 of 75 in this shift, Chemistry question 15 of 25, Section A.

For the following Friedel Craft's alkylation reaction, which of the statements are correct? [figure: benzene + n-propyl chloride (CH3CH2CH2Cl\mathrm{CH_3CH_2CH_2Cl}) with anhydrous AlCl3\mathrm{AlCl_3} →\rightarrow Alkylbenzene] A. Major product is n-propyl benzene. B. iso-propyl carbocation intermediate is also generated. C. Multiple substitution is inevitable. D. Introducing electron-donating substituent on benzene will not produce any alkyl benzene. Choose the correct answer from the options given below:

The figure, in words

Reaction scheme: benzene + 1-chloropropane (zigzag chain ending in Cl), anhydrous AlCl3, giving alkylbenzene.
  1. (1)A and D only
  2. (2)B and C onlyOfficial answer
  3. (3)A and C only
  4. (4)B and D only

Official answer

Option 2

NTA final key.

Chapter
Haloalkanes and Haloarenes
Topic
Aromatic Hydrocarbons
Idea tested
Friedel-Crafts Alkylation

Same idea in other shifts

Asked 2× in all
  1. 4 Apr 2026, Shift 2 · Q56Match the LIST-I with LIST-II List-I (Reaction): A. Williamson Synthesis B. Friedel Craft Reaction C. Bromination of vinyl benzene D.…EasyMatch the list

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.