JEE Main 2026 · ChemistryMultiple choiceDiagram basedHardMulti-step
JEE Main 5 April 2026, Shift 1, Chemistry Q64
Question 64 of 75 in this shift, Chemistry question 14 of 25, Section A.
"P" is a hydrocarbon of molecular formula:- . On ozonolysis, "P" forms "Q". "Q" on treatment with alkali under reflux condition produces "R", which on treatment with / NaOH gives a yellow precipitate. Acidification of the solution gives "S". The structure of "S" is given below:-
[figure: cyclopentene ring with a CH group on one double-bond carbon and a COOH group on the other double-bond carbon]
The correct structure of "P" is
The figure, in words
Stem figure: structure S, a cyclopentene with CH3 and COOH on the two alkene carbons. Options are alkene structures (cyclohexenes / cyclopentene).- (1)[figure: cyclohexene with CH substituents at the 1 and 4 positions (para to each other); double bond at the ring bottom right]
- (2)[figure: cyclohexene ring bearing a (ethyl) group on a double-bond carbon]
- (3)[figure: cyclopentene bearing a group on one double-bond carbon and a group on the other double-bond carbon]
- (4)[figure: cyclohexene bearing a group on each of the two double-bond carbons (1,2-dimethylcyclohexene)]Official answer
Official answer
Option 4
NTA final key.
- Topic
- Alkenes and Alkynes
- Idea tested
- Reductive Ozonolysis Products